Chemistry2/12/2020
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Three samples of a solid substance composed of elements A and Z were prepared. The first contained 4.31 g A and 7.70 g Z. The second sample was 35.9% A and 64.1% Z. It was observed that 0.718 g A reacted with Z to form 2.00 g of the third sample. Show that these data illustrate the law of definite composition. | Sample (1): ratio of masses (Z/A) = 7.70/4.13 = 1.785 Sample (2): ratio of masses (Z/A) = 64.1/35.9 = 1.785 Sample (3): ratio of masses (Z/A) = (2.00-0.718)/0.718 = 1.785 |