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level: IR BANDS

Questions and Answers List

Question	Answer
Restricted rotation about N-CO bond produces diastereomers, giving two bands in the case of secondary amides	A
C=C unconjugated gives a very weak absorption but when conjugated, the C=C bond gives a much stronger absorption, found typically in many steroids	B
C=C aromatic: the band at 1600 cm^-1 may be weak unless the aromatic ring is substituted with polar substituents, e.g., a phenol, aromatic ether, or aromatic amine free base	C
N-H bend is often obscured by stronger aromatic C=C stretching bands	D
SO2 bands: although this absorption is in the fingerprint region , these bands are quite prominent in sulphonamides	E
C-H bending in many cases is not very distinctive in drug molecules because of the complexity of the fingerprint region	F