Physics - Heat and Temperature: Q = ? Q = ?
m = 50 ml = 50 g = 0.05 kg m = 0.05 kg
c = 4180 J kg-1 K-1 L = 22.5 x 10^5 J kg-1
ΔT = 100 -20 = 80 K

Q = 16 800 J Q = 112 500 J

total Q = 129 300 J

Question

Q = ?                                            Q = ?
m = 50 ml = 50 g = 0.05 kg       m = 0.05 kg
c = 4180 J kg-1 K-1                     L = 22.5 x 10^5 J kg-1 
ΔT = 100 -20 = 80 K

Q = 16 800 J                               Q = 112 500 J

total Q = 129 300 J

Lauren Noack · Accepted Answer

50 ml of water is heated from a room temperature of 20 ˚C to its boiling point at 100 ˚C . It is boiled at this temperature until it is completely evaporated. How much energy in total was required to raise the temperature and boil the water?

Physics - Heat and Temperature

Q = ? Q = ? m = 50 ml = 50 g = 0.05 kg m = 0.05 kg c = 4180 J kg-1 K-1 L = 22.5 x 10^5 J kg-1 ΔT = 100 -20 = 80 K Q = 16 800 J Q = 112 500 J total Q = 129 300 J

50 ml of water is heated from a room temperature of 20 ˚C to its boiling point at 100 ˚C . It is boiled at this temperature until it is completely evaporated. How much energy in total was required to raise the temperature and boil the water?

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