Factorize the given expression: 27x³ - 63x²+ 49x - 343/27

Compare the given expression to the standard cubic algebraic identity to factorise (a - b)³ = a³ - 3a²b + 3ab² - b³ Compare 27x³ - 63x² + 49x - 343/27 to a³ - 3a²b + 3ab² - b³ We can deduce that 27x³ = a³ or (3x)³ = a³ ∴ a = 3x And 343/27 = b³ or [73]³ = b³ ∴ b = 7/3 So, 27x³ - 63x²+ 49x - 343/27 (3x)³ - 3(3x)²(7/3) + 3(3x)[7/3]² - [7/3]³ = [3x−7/3]³ = [3x−7/3] [3x−7/3] [3x−7/3]