Using the Sodium Hydroxide / Metal Ions Test, what Colour Precipitate would appear with Calcium, Ca²+ Copper, Cu²+ Iron (II), Fe²+ Iron (III), Fe³+ Zinc, Zn²+ Give the Equations

-For Calcium, a White Precipitate would Form [Ca²+ + 2OH- --> Ca(OH)₂] -For Copper, a Blue Precipitate would Form [Cu²+ + 2OH- --> Cu(OH)₂] -For Iron (II), a Green Precipitate would Form [Fe²+ + 2OH- --> Fe(OH)₂] -For Iron (III), a Brown Precipitate would Form [Fe³+ + 3OH- --> Fe(OH)₃] -For Zinc, a White Precipitate would form, but then Redissolves to make a Colourless Solution [Zn²+ + 2OH- --> Zn(OH)₂] --> [Zn(OH)₂ + 2OH- --> Zn(OH)₄²-]